Answer:
∠ DCV = ∠ VBD = 50°
Step-by-step explanation:
The inscribed angles DCV and VBD are half the measure of their intercepted arcs, that is
∠ DCV = [tex]\frac{1}{2}[/tex] DV = [tex]\frac{1}{2}[/tex] × 100° = 50°
∠ VBD = [tex]\frac{1}{2}[/tex] DV = [tex]\frac{1}{2}[/tex] × 100° = 50°
