Question

Brandon enters bike races.He bikes 8 1/2 miles every 1/2 hour. complete a table to find how far Brandon bikes for each time interval.

Answer 1

12. Since there is no table given I will assume that what you want me to do is to show that Unit rate of Brandon’s biking. SO here are the data that we need: => 8 and ½ miles = 8.5 miles => ½ hour = .5 hours or 30 minutes Now, let’s solve for the unit rate => SO in every 30 minutes he bikes around 8.5 miles => Since 1 hour is equals to 30 minutes, simply multiply 8.5 by 2 => 8.5 * 2 = 17miles => 17 miles / hour

Answer 2

The distance of Brandon’s bike in each interval of time can be represented in the attached Table 1.

Further explanation:

Given:

Brandon enters in to the bike race and he bikes $8\frac{1}{2}\text{ miles}$ in every $\frac{1}{2}\text{ hour}$.

Calculation:

It is given that in every $\frac{1}{2}\text{ hour}$ Brandon bikes $8\frac{1}{2}\text{ miles}$.

The distance $8\frac{1}{2}\text{ miles}$ is in the form of mixed fraction.

Therefore, the distance $8\frac{1}{2}\text{ miles}$ can be written in the form of decimal as follows:

$\boxed{8\frac{1}{2}\text{ miles}\rightarrow8.5\text{ miles}}$

 

Brandon bike's $8.5\text{ miles}$ in every $\frac{1}{2}\text{ hour}$.

We know that $1\text{ hour}$ is equivalent to $60\text{ minutes}$.

So, $0.5\text{ hour}$ can be converted into minutes as follows:

$\boxed{\begin{aligned}1\text{ hour}\rightarrow60\text{ minutes}\\0.5\text{ hour}\rightarrow30\text{ minutes}\end{aligned}}$  

Therefore, in every $30\text{ minutes}$ Brandon bikes $8.5\text{ miles}$.

So, in next $30\text{ minutes}$ Brandon also bikes $8.5\text{ miles}$.

In every $1\text{ hour}$ Brandon travels $\boxed{8.5+8.5=17\text{ miles}}$.

In every $1:30\text{ hour}$ Brandon travels $\boxed{17+8.5=25.5\text{ miles}}$.

Method 2:

Speed of Brandon’s bike can be calculated as ,

$\boxed{\text{Speed}=\dfrac{d}{t}}$        …… (1)

Here, $d$ is the distance and $t$ is the time.

The distance is $8.5\text{ miles}$ and time is $0.5\text{ hour}$.

Now, substitute $d=8.5$ and $t=0.5$ in the equation (1) to obtain the speed as follows:

$\begin{aligned}\text{Speed}&=\dfrac{8.5}{0.5}\\&=17\text{ miles per hour}\end{aligned}$

 

Therefore, the rate of travelling of Brandon’s bike is $17\text{ miles per hour}$.

The distance of Brandon’s bike in each interval of time can be represented in the attached Table 1.

Learn more:

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Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Speed, time and distance

Keywords:  Distance, Brandon’s bike, interval, time, race, mixed fraction, distance, decimal, hour, minutes, rate, fraction, velocity, 1/2 miles, 1/2 hour.