Question

Write an equation of the line that passes through the given point and is perpendicular to the given line.
(–6, –4); y = 1/3x + 1
Group of answer choices

y = -1/3x + 1

y =1/3x – 22

y = -3x + 14

y = -3x – 22

Answer 1

Answer:

y = - 3x - 22

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = $\frac{1}{3}$ x + 1 ← is in slope- intercept form

with slope m = $\frac{1}{3}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{\frac{1}{3} }$ = - 3 , then

y = - 3x + c ← is the partial equation

To find c substitute (- 6, - 4) into the partial equation

- 4 = 18 + c ⇒ c = - 4 - 18 = - 22

y = - 3x - 22 ← equation of perpendicular line