Question

How many liters of a 10% alcohol solution must be mixed with 40 liters of a 50% alcohol
solution to obtain a 40% alcohol solution?

Answer 1

Answer:

13 $\frac{1}{3}$

Step-by-step explanation:

$20+.1x=.4\left(40+x\right)$

x=40/3 = 13 $\frac{1}{3}$