Question

What else would need to be congruent to show that ABC= A DEF by the
AAS theorem?
B
E
Given:
ZA ZD
AB DE
A
F
A. AC = DF
B. ZCE ZF
C. BC = BC
D. BEZE

Answer 1

Answer:

$\angle C \cong \angle F$

Step-by-step explanation:

Given

$\angle A \cong \angle D$

$AB \cong DE$

See attachment

Required

What proves $\triangle ABC \cong \triangle DE F$ by AAS

We have:

$\angle A \cong \angle D$ --- Angle

$AB \cong DE$ --- Side

We need to prove that one more angle are congruent

$\angle B \cong \angle E$

The above angles are congruent; however, it will prove $\triangle ABC \cong \triangle DE F$ by ASA

So, we make use of:

$\angle C \cong \angle F$ because it completes the proof by AAS