Respuesta :
Answer:
(a) 160000 kV/m
(b) 1336 keV
Explanation:
(a) magnetic filed, B = 10 T
energy of electron, E = 740 eV
mass of electron, m = 9.1 x 10^-31 kg
Let v be the velocity of electron.
E = 1/2 mv^2
740 x 1.6 x 10^-19 = 0.5 x 9.1 x 10^-31 x v^2
v = 1.6 x 10^7 m/s
v = E / B
E = v x B = 1.6 x 10^7 x 10 = 16 x 10^7 V/m
E = 160000 kV/m
(b) E = 16 x 10^7 V/m
B = 10 T
Let v be the velocity of protons.
v = E / B = 16 x 10^7 / 10 = 1.6 x 10^7 m/s
Kinetic energy of proton, E = 1/2 mv^2
= 0.5 x 1.67 x 10^-27 x 1.6 x 1.6 x 10^14
= 2.14 x 10^-13 J = 1336000 eV = 1336 keV
(a)The value of E will be 60000 kV/m
(b)The kinetic energy of a proton will be 1336 keV.
What is a magnetic field?
It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.
B is the magnetic field = 10 T
E is the energy of electron= 740 eV
m is the mass of electron= 9.1 x 10^-31 kg
v be the velocity of the electron= 1.6×10⁷
[tex]E = 1/2 mv^2\\\\ 740 \times 1.6 \times 10^-{19} = 0.5 \times 9.1 \times 10^-{31 \times v^2[/tex]
[tex]\rm v = 1.6 x 10^7 m/s \\\\ v = E / B\\\\ E = v \times B \\\\ \rm E=1.6 x 10^7 \times 10 \rm E= 16 \times 10^7 V/m \\\\ \rm E = 160000 kV/m[/tex]
Hence the value of E will be 60000 kV/m.
(b)The kinetic energy of a proton will be 1336 keV.
The kinetic energy of the proton is found by the formula;
[tex]\rm E_K= \frac{1}{2} mv^2[/tex]
[tex]\rm E = 16 x 10^7 V/m\\\\ \rm B = 10 T \\\\ \rm v = \frac{E}{B} = \frac{16 x 10^7 }{10} \\\\ \rm E_K= 1.6 x 10^7 m/s \\\\ \rm E_K= 0.5 \times 1.67 \times 10^{-27}\times 1.6 \times 1.6 \times 10^{14} \\\\ \rm E_K= 2.14 \times 10^{-13} J = 1336000 eV = 1336 keV[/tex]
Hence the kinetic energy of a proton will be 1336 keV.
To learn more about the magnetic field refer to the link;
https://brainly.com/question/19542022
