Question

Two forces act on the screw eye. If F = 600 N, determine the magnitude of the resultant force and the angle θ if the resultant force is directed vertically upward.

Answer 1

Answer:

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Answer 2

The magnitude of the resultant force is 919.6 N and the value of angle θ is 36.87⁰.

Resultant of the two forces

The resultant of the two forces is determined by resolving the force into x and y component as shown below;

$F_1_x + F_2x_x = F_R_x \ --- (1) \\\\F_1_y + F_2_y = F_R_y\ ---(2)$

where;

• F1 = 500 N
• F2 = 600 N

Value of Angle θ

The value of Angle θ is determined from equation (1)

-500sinθ + 600sin(30) = 0

500sinθ = 600sin(30)

500sinθ = 300

sinθ = 3/5

θ = 36.87⁰

Resultant of the two forces

The resultant of the forces is determined using the second equation;

500cosθ + 600cos(30) = R

500 x cos(36.87) + 600 x cos(30) = R

919.6 N = R

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