Question

Assume that I = E/(R + r), prove that 1/1 = R/E + r/E​

Answer 1

$\implies {\blue {\boxed {\boxed {\purple {\sf { \frac{1}{I} = \frac{R}{E} + \frac{r}{E} }}}}}}$

$\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}$

$I = \frac{ E}{ R + r}$

$➺\:\frac{I}{1} = \frac{E}{R + r}$

Since $\frac{a}{b} = \frac{c}{d}$ can be written as $ad = bc$, we have

$➺ \: I \: (R + r) = E \times 1$

$➺ \: \frac{1}{I} = \frac{R + r}{E}$

$➺ \: \frac{1}{I} = \frac{R}{E} + \frac{r}{E}$

$\boxed{ Hence\:proved. }$

$\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}$