What is the value of [tex]a[/tex] ?

Answer:
hello :
the graph passes by ( 3; -1/3) : f(3) = -1/3
a/ (3)^3 = -1/3
a / 27 = -1/3
a/9 = - 1
a = - 9
We have the point:
[tex]\left(3,\ -\dfrac{1}{3}\right)[/tex]
Put the coordinates of the point to the equation of the function f:
[tex]f(x)=\dfrac{a}{x^3}\to y=\dfrac{a}{x^3}\\\\\left(3,\ -\dfrac{1}{3}\right)\to x=3,\ y=-\dfrac{1}{3}\\\\\dfrac{a}{3^3}=-\dfrac{1}{3}\\\\\dfrac{a}{27}=-\dfrac{1}{3}\qquad\text{multiply both sides by 27}\\\\a=-\dfrac{1}{3}\cdot27\\\\\boxed{a=-9}[/tex]