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PLEASE HELP!!!


Solve for x in the following equation!!!

[tex]sin(\frac{3\pi }{2}+x) + sin(\frac{3\pi }{2}+x)=-2[/tex]

Respuesta :

Answer:

Step-by-step explanation:

First we'll simplify this using the Sum Identity for sin(x + y) where [tex]x=\frac{3\pi}{2}[/tex] and y = x. Notice we have 2 of those so we simplify first into

[tex]2sin(\frac{3\pi}{2}+x)=-2[/tex] and divide away the 2 on the left to get

[tex]sin(\frac{3\pi}{2}+x)=-1[/tex] and now we'll expand:

[tex]sin\frac{3\pi}{2}cosx+cos\frac{3\pi}{2}sinx=-1[/tex] and go to your unit circle to find the sin and cos of [tex]\frac{3\pi}{2}[/tex] and fill in where they go:

(-1cosx + 0sinx) = -1 which simplifies to

-1cosx = -1 so

cosx = 1 and

x = 0 or 2π, depending upon what your interval is.

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