Question

Allicin (C6H10OS2) contains 59.9 g of carbon, 21.7 g of hydrogen, 24.4 g of oxygen, and sulfur. What is the mass percent of sulfur in a 162 g sample of the compound?
a) 13.40%
b) 15.06%
c) 21.04%
d) 34.57%
e) 36.98%

Answer 1

it will be 56g and then
the percentage

Answer 2

Answer : The correct option is, (d) 34.57 %

Explanation: Given,

Mass of C = 59.9 g

Mass of H = 21.7 g

Mass of O and S = 24.4 g

Mass of sample = 162 g

First we have to calculate the mass of sulfur.

Total mass of allicin = Mass of C + Mass of H + Mass of O and S

Total mass of allicin = 59.9 + 21.7 + 24.4

Total mass of allicin = 106 g

Mass of sulfur = Mass of sample - Total mass of allicin

Mass of sulfur = 162 - 106

Mass of sulfur = 56 g

Now we have to calculate the mass percent of sulfur.

Formula used :

$\text{Mass percent of sulfur}=\frac{\text{Mass of sulfur}}{\text{Mass of sample}}\times 100$

Now put all the given values in this formula, we get:

$\text{Mass percent of sulfur}=\frac{56}{162}\times 100=34.57\%$

Therefore, the mass percent of sulfur is 34.57 %