Question

What is the slope of a line that is perpendicular to the line joining point A(4, -1) and point B(3, 3)?

Answer 1

Answer:

$m_1= \frac{1}{4}$

Step-by-step explanation:

Given

$A = (4,-1)$

$B =(3,3)$

Required

Slope of line perpendicular to AB

First, we calculate the slope of AB using:

$m=\frac{y_2 -y_1}{x_2 -x_1}$

This gives:

$m=\frac{3--1}{3-4}$

$m=\frac{4}{-1}$

$m=-4$

The line perpendicular to AB has the following slope (m1):

$m_1= -\frac{1}{m}$

So, we have:

$m_1= -\frac{1}{-4}$

$m_1= \frac{1}{4}$