Question

A 0.495-kg hockey puck, moving east with a speed of 4.50 m/s , has a head-on collision with a 0.720-kg puck initially at rest. Assuming a perfectly elastic collision, what will be the speed (magnitude of the velocity) of each object after the collision?

Answer 1

Answer:

a)  $v_1=-0.833m/s$

b)  $V_2=12.5m/s$

Explanation:

From the question we are told that:

Hockey puck Mass $m_1=0.495kg$

Hockey puck Speed $u_1=4.50m/s$

Puck Mass $m_2=0.720kg$

Assuming

Initial speed of Puck $u_2=0$

Generally the equation for Speed of First Puck is mathematically given by

 $v_1=(\frac{m_1-m_2}{m_1+m_2})*v_1+(\frac{2m_2}{m_1+m_2})u_2$

 $v_1=(\frac{0.495-0.720}{0.495+0.720})*4.50+0$

 $v_1=-0.833m/s$

Generally the equation for Speed of Second Puck is mathematically given by

 $V_2=(\frac{2m_1}{m_1+m_2})u_2-(\frac{m_1-m_2}{m_1+m_2})v$

 $V_2=(\frac{2*0.495}{0.495*0.720})*4.50-0$

 $V_2=12.5m/s$