Question

A weather balloon containing helium with a volume of 410.0 L rises in the atmosphere and is cooled from 17∘
∘
C to -27∘
∘
C. The pressure on the gas is reduced from 110.0 kPa to 25.0 kPa. What is the volume of the gas at the lower temperature and pressure? What law did you use to solve?

Answer 1

Answer:

V₂ = 1500 Liters ( 2 sig. figs.)

Explanation:

Given the following gas law variables:

P₁ = 110.0KPa           P₂ = 25KPa

V₁ = 410 Liters          V₂ = ?

T₁ = 17°C ( = 290K)   T₂ = -27°C  ( = 248K)

P₁V₁/₁T₁ = P₂V₂/T₂  =>  V₂ = V₁(P₁/P₂)(T₂/T₂)

V₂ = 410L(110.0KPa/25KPa)(248k/290K) = 1542 L (calc. ans.)

V₂ = 1500 Liters ( 2 sig. figs.)