Question

carbon dioxide gas evolve during the fermentation of sugar which was collected at 22.5°C and 0.945 ATM after perfect strangers in the volume was found to be 25.0 ML how many grams of carbon dioxide were collected

Answer 1

Answer:

0.043 grams

Explanation:

We can find the mass of carbon dioxide as follows:

$m = n*M$

Where:

n: is the number of moles

M: is the molar mass = 44.01 g/mol

First, we need to calculate the number of moles. We can use the Ideal gas equation:

$PV = nRT$

Where:

P: is the pressure = 0.945 atm

V: is the volume = 25.0 mL  

R: is the gas constant = 0.082 L*atm/(K*mol)

T: is the tempearture = 22.5 °C

$n = \frac{PV}{RT} = \frac{0.945 atm*25 mL*\frac{1 L}{1000 mL}}{0.082 L*atm/K*mol*(22.5 + 273) K} = 9.75 \cdot 10^{-4} moles$

Hence, the mass is:

$m = 9.75 \cdot 10^{-4} moles*44.01 g/mol = 0.043 g$

Therefore, 0.043 grams were collected.

                         

I hope it helps you!