Answer:
f = 0.365 Hz
Explanation:
The angular velocity of a simple pendulum is
w = [tex]\sqrt{g/L}[/tex]
angular velocity and frequency are related
w = 2π f
we substitute
2π f = [tex]\sqrt{g/L}[/tex]
Let's find the initial length of the pendulum
L = [tex]\frac{g}{4\pi^2 } \ f_o[/tex]
L₀ = [tex]\frac{9.8}{4 \pi ^2} \ 0.4[/tex]
L₀ = 0.6206 m
Indicates that the length of the chord triples
L = 3 L₀
L = 3 0.6206
L = 1.8618 m
let's find the frequency
f = [tex]\frac{1}{2\pi } \ \sqrt{\frac{9.8}{1.8618} }[/tex]
f = 0.365 Hz
