Answer:
option A
Step-by-step explanation:
[tex]y - 9 = \frac{2}{3} (x + 7)\\\\ y - 9= \frac{2}{3} x + \frac{14}{3}\\\\ y = \frac{2}{3} x + \frac{14}{3} + 9\\\\y = \frac{2}{3}x + \frac{14 +27}{3}\\\\y = \frac{2}{3}x + \frac{41}{3}\\\\[/tex]
Therefore, slope of the given line is
[tex]m_ 1 = \ \frac{2}{3}[/tex]
Find the slope of the new line
The product of slope of lines perpendicular to each other = - 1
That is ,
[tex]m_ 1 \times m_2 = - 1\\\\\frac{2}{3} \times m_ 2 = - 1\\\\m_ 2 = - \frac{3}{2}[/tex]
Find the equation of the line.
[tex]Let \the \ given \ points \ be \ ( x_ 2 , y _ 2 ) = ( 2 , 3 ) \\\\(y- y_2) = m_2 (x - x_ 2)\\\\( y - 3 ) = - \frac{3}{2}(x - 2)\\\\y = -\frac{3}{2}x + \frac{3 \times 2}{2} + 3\\\\y = - \frac{3}{2} x +3+3\\\\y = - \frac{3}{2} x +6\\\\[/tex]
