What is the pH of a 1.00 M aqueous solution of a weak diprotic acid H2Y if its Ka1 is equal to 6.9x10-5 and Ka2 is equal to 5.4x10-12

Respuesta :

The pH of the diprotic acid H2Y is =

6.15 × 10-17

Calculation of pH

A diprotic acid is a type of acid that contains two hydrogen atoms in its molecules which has the ability to be replaced when involved in a chemical reaction.

A weak diprotic acid is the type of acid that yields hydronium ions and bicarbonate ions in small amounts when involved in a chemical reaction.

The pH is defined as the degree of how acidic or how basic a substance is when measured against a scale.

The Ka1 of the weak diprotic acid = 6.9x10-5

The Ka2 of the weak diprotic acid = 5.4x10-12

Using the formula;

pH = (pKa1 + pKa2)/2

pH = (6.9x10-5 + 5.4x10-12)/2

pH= 12.3 ×10-5×10-12

pH= 12.3 × 10-17/2

pH= 6.15 × 10-17

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