Respuesta :

Answer:

13 units

Step-by-step explanation:

(-7 , 5) = (x1 , y1)

(6 , 5) = (x2 , y2)

distance = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]

=[tex]\sqrt{{6 - (-7)}^2 + (5 - 5)^2}[/tex]

=[tex]\sqrt{(6 + 7)^2 + (0)^2}[/tex]

=[tex]\sqrt{(13)^2 + 0}[/tex]

=[tex]\sqrt{169}[/tex]

= 13 units

Answer:

13 units

Step-by-step explanation:

Hi there!

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex] where two given points are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]

Plug in the given points (-7,5) and (6,5)

[tex]d=\sqrt{(6-(-7))^2+(5-5)^2}\\d=\sqrt{(6+7)^2+(5-5)^2}\\d=\sqrt{(13)^2+(0)^2}\\d=\sqrt{(13)^2}\\d=13[/tex]

Therefore, the distance between the two points is 13 units.

I hope this helps!

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