Respuesta :
Answer:
A. 2.3 L
B. 6.10 L
C. 0.060 L
Explanation:
The question asks the volume of a 0.200 M solution of ethanol that contains certain number of moles of ethanol.
The M in the 0.200 M stands for Molarity. This is a unit of concentration that can be expressed as:
Molarity = moles of solute / Liters of solution
In this case:
0.200 M = moles of ethanol / Liters of solution
So from the formula we can get that we can calculate the volume of the solution, as Liters of solution, given the moles in each case as:
Liters of solution = moles of ethanol / 0.200 moles/L
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A. 0.45 mol ethanol
Liters of solution = 0.45 moles / 0.200 moles/L = 2.25 L = 2.3 L
B. 1.22 mol ethanol
Liters of solution = 1.22 moles / 0.200 moles/L = 6.10 L
C. 1.2 x 10⁻² mol ethanol
Liters of solution = 1.2 x 10⁻² moles / 0.200 moles/L = 0.060 L
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Note: Each answer is given with the correct number of significant figures which results from the least number of significant figures in the given used values in each calculation.
To found 0.45 mol its necessary 2.25L, to found 1.22 mol its necessary 6.1L and to found 1.2x10^-2 mol its necessary 0.06L.
Mole calculation
To calculate the volume needed for each amount of mole, use the following expression:
[tex]M =\frac{mol}{v}[/tex]
Thus, with the molarity value we can calculate the volume for each number of moles, so that:
A. [tex]0.2 = \frac{0.45}{v}[/tex]
[tex]v= 2.25 L[/tex]
B. [tex]0.2 = \frac{1.22}{v}[/tex]
[tex]v = 6.1L[/tex]
C. [tex]0.2 = \frac{1.2\times 10^{-2}}{v}[/tex]
[tex]v = 0.06L[/tex]
So, to found 0.45 mol its necessary 2.25L, to found 1.22 mol its necessary 6.1L and to found 1.2x10^-2 mol its necessary 0.06L.
Learn more about mole calculation in: brainly.com/question/2845237
