Answer:
Sn --> Sn2+ + 2e-
Explanation:
At anode oxidation reaction occur. In this reaction Sn is getting oxidized to state +2 while Ag is reduced from +1 to 0.
Hence, reaction at anode will be
Sn (s) --> Sn2+ (aq) + 2e-
At cathode the following reaction occur
2 Ag⁺ + 2e- ---> 2Ag (s)