Question

If I have 340 mL of a 0.5 M NaBr solution, what will the concentration be if I add 560 mL more water to it?

Answer 1

Answer:

The correct answer is "0.31 M".

Explanation:

Given,

Volume,

$V_1=340$

$V_2=560$

Molarity,

$M_1=0.5$

Let the M₂ be "x".

By using the dilution formula, we get

⇒ $M_1V_1=M_2V_2$

then,

⇒ $0.5\times 340=x\times 560$

⇒          $170=x\times 560$

⇒             $x=\frac{170}{560}$

⇒                $=0.31 \ M$