Question

A chef cooked seven kilograms of mashed potatoes for a dinner
party. If the guests only ate three-quarters of the amount he cooked,
how much did they eat?.....................plz hurry up 

Answer 1

$7* \frac{3}{4} = \frac{7*3}{4} = \frac{21}{4} = \frac{20+1}{4} = \frac{20}{4} + \frac{1}{4} =5+ \frac{1}{4} =5.25$

Answer 2

Answer:

Hence, the amount of potatoes they ate is:

$\dfrac{21}{4}kg=5.25kg$

Step-by-step explanation:

A chef cooked seven kilograms of mashed potatoes for a dinner

party.

Now it is given that:

If the guests only ate three-quarters of the amount he cooked,

We have to find the amount they ate?

(  Three-quarters is an amount that is three out of four equal parts of something )

i.e. the guest ate:

3/4 of 7 kg of mashed potatoes.

which is given by:

$\dfrac{3}{4}\times 7=\dfrac{21}{4}kg=5.25kg$

Hence, the amount of potatoes they ate is:

$\dfrac{21}{4}kg=5.25kg$