yahir52 yahir52

29-05-2021
Chemistry

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DrTobiasFunke DrTobiasFunke

29-05-2021

Answer:

135.80 g of Ag

Explanation:

[tex]40gCu *\frac{1mol Cu}{63.546g Cu} *\frac{2mol Ag}{1molCu} *\frac{107.868g Ag}{1mol Ag}[/tex]

~ 135.80 g of Ag

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