Question

What is the pressure of a 0.108 mol sample of helium gas at a temperature of 293 K if its volume is 0.505 L?

Answer 1

Answer:

P = 5.14 atm

Explanation:

Given that,

Pressure of the gas, P = 0.108 mol

Temperature, T = 293 K

Volume, V = 0.505 L

We need to find the pressure of the gas. We know that, according to ideal gas equation,

PV = nRT

Where

P is pressure and R is gas constant

$P=\dfrac{nRT}{V}\\\\P=\dfrac{0.108 \times 0.0821\times 293}{0.505}\\\\P=5.14\ atm$

So, the pressure of the gas is equal to 5.14 atm.