Question

Luke has 1/3 of a package of dried apricots. He divides the dried apricots equally into 3 small bags. Luke gives one of the bags to a friend and keeps the other two bags for himself. What fraction of the oringial package of dried apricots did Luke keep for himself?

Answer 1

1/3 ÷ 3 = $\frac{1}{9}$ for each

Luke will stay with a total of:

$\frac{1}{9}$ (x 3) = $\frac{3}{9}$

$\frac{3}{9} - \frac{1}{9} = \frac{2}{9}$

Hope it helped!

Answer 2

Answer: 2/9


Explanation:

$\cfrac{1}{3} \div 3 = \cfrac{1}{3} \times \cfrac{1}{3} = \cfrac{1}{9}$

$\cfrac{1}{3} - \cfrac{1}{9} = \cfrac{3}{9} - \cfrac{1}{9} = \cfrac{2}{9}$