Question

The width of a rectangle is 5 times its length. The perimeter is
53.
Find the width and length of the rectangle.

HELP. MATH FINAL DUE SOON....

Answer 1

Answer:

L = x

W = 5x

P = 2 (L + W)

53 = 2(x + 5x)

53 = 2(6x)

53 = 12x

x = 4/5/12

L = 4/5/12

W = 22/1/12