Question

If 238 J of heat is absorbed by a sample of metal with a mass of 40.7 g, and it raises the temperature from 20.0°C to
32.4°C, what is the specific heat capacity of the metal? (show your work)

Answer 1

Explanation:

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Answer 2

The specific heat capacity of the metal is 0.471 J/g°C .

How do we calculate specific heat?

Specific heat of the metal will be calculated by using the below equation:

Q = mcΔT

Or c = Q/mΔT, where

• m = mass = 40.7g
• Q = absorbed heat = 238J
• ΔT = change in temperature = 32.4 - 20 = 12.4°C

On putting all these values, we get

c = 238 / (40.7)(12.4) = 0.471 J/g°C

Hence value of specific heat capacity of metal is 0.471 J/g°C.

To know more about specific heat, visit the below link:
https://brainly.com/question/22947190

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