Answer:
x=+[tex]\frac{\sqrt{4y-7}-1 }{2}[/tex]
Step-by-step explanation:
Quadratic function =( -b+[tex]\sqrt{b^2+4ac}[/tex] )/2a
x^2+x+2-y=0
x=-1+[tex]\sqrt{1^2-4(2-y)}[/tex] /2
x=-1+[tex]\sqrt{4y-7}[/tex] /2
x=+ [tex]\frac{\sqrt{4y-7}-1 }{2}[/tex]
Pretty sure this is right. Would appreciate a brainliest
