The expression f(x)/g(x) defines function h(x)=3x^2+12x.The answer is C.
We have given that,
[tex]f(x)=3x^2+9x^2-12x[/tex]
[tex]g(x)=x-1[/tex]
and, [tex]h(x)=3x^2+12x[/tex]
What is the division of the function?
Suppose f(x) and g(x) are function,
[tex](\frac{f}{g}) (x)=\frac{f(x)}{g(x)}[/tex]
So we have given function us
[tex]f(x)=3x^2+9x^2-12x[/tex]
[tex]g(x)=x-1[/tex]
We have divide f(x) by g(x)
[tex]=\frac{3x^3+9x^2-12x}{x-1}[/tex]
[tex]=3x\left(x+4\right)[/tex]
[tex]=3x^2+12x[/tex]
Therefore we get the expression f(x)/g(x) defines function h.
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