Respuesta :

Answer: [tex]-7\ \text{and}\ 5[/tex]

Step-by-step explanation:

Given

The equation is [tex]\left(x+1\right)^2-36=0[/tex]

Solving it

[tex]\Rightarrow \left(x+1\right)^2=36\\\\\Rightarrow \left(x+1\right)=\pm\sqrt{36}\\\\\Rightarrow x+1=\pm6\\\Rightarrow x=-7,5[/tex]

So, the lesser value of [tex]x[/tex] is [tex]-7[/tex] and the greater value is [tex]5[/tex].

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