In a lab experiment, 610 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 23 hours. How long would it be, to the nearest tenth of an hour, until there are 1040 bacteria present?

Given that in a lab experiment, 610 bacteria are placed in a petri dish, and the conditions are such that the number of bacteria is able to double every 23 hours, to determine how long would it be, to the nearest tenth of an hour, until there are 1040 bacteria present, the following calculation must be performed:

610X = 1040

X = 1040/610

X = 1.7049

2 = 23

1.7049 = X

1.7049 x 23/2 = X

39.2131 / 2 = X

19.6 = X

100 = 60

60 = X

60 x 60/100 = X

36 = X

Therefore, it would take 19 hours and 36 minutes until there are 1040 bacteria present.

In a lab experiment, 610 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 23 hours. How long would it be, to the nearest tenth of an hour, until there are 1040 bacteria present?​

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In a lab experiment, 610 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 23 hours. How long would it be, to the nearest tenth of an hour, until there are 1040 bacteria present?