Answer:
The thickness of the film is = 3.183e-9m
Explanation:
It will help us if we understand that the shape of the circular film can be approximated to be a cylinder. The height of this cylinder, or its thickness, in this case, will be very small.
Since we can approximate the shape of the drop of oil to be a cylinder, after it has spread out on the surface of the water, we can use the cylindrical geometric formulas to find out how thick the film is.
The volume of a cylinder = [tex]\pi r^2 h[/tex]
our radius is given as [tex]10^{-1}m = 0.1m[/tex]
the volume is [tex]10 ^{-10} m^3=1e-10m^3[/tex]
Remember that our task is to find the height of the cylinder. We can do this by making the height the subject of the formula.
[tex]h = \frac{Volume}{\pi r^2} = \\\\\frac{1e-10}{\pi \times 0.1^2} = 3.183e-9m[/tex]
Therefore, the thickness of the film is = 3.183e-9m
