Question

In the following figure, the value of x is
B.
X
41°
с
11
A
Note: Round your answer to the nearest tenth.

Answer 1

Given:

In a right angle triangle ABC, $m\angle B=90^\circ, BC=x, AC=11, m\angle C=41^\circ$.

To find:

The value of x to the nearest tenth.

Solution:

In a right angle triangle,

$\cos\theta =\dfrac{Adjacent}{Hypotenuse}$

In the given right angle triangle ABC,

$\cos \angle C =\dfrac{BC}{AC}$

$\cos (41^\circ) =\dfrac{x}{11}$

$11(0.7547) =x$

$8.3017 =x$

Round the answer to the nearest tenth.

$x\approx 8.3$

Therefore, the value of x is 8.3 units.