Question

A runner accelerates to a velocity of 5.36 m/s due west in 3.00 seconds. his average acceleration is 0.640 m/s2 also directed due west. what was his velocity when he began accelerating?

Answer 1

Given, acceleration of the runner, a = 0.640 m/s²

Final velocity of the runner, v = 5.36 m/s

Time, t = 3 s

Let the velocity of the runner be u when he began accelerating.

Using the first equation of motion,

v=u+at

Substituting the values we get,

$5.36= u + 0.64*3$

$u=5.36-1.92$

=3.44 m/s

The velocity of the runner when he began accelerating is 3.44 m/s.