Question

How many moles of oxygen are necessary to completely react with propane (C3H8) to produce 16.3 mol of water according to the following balanced chemical equation? ________________________________________________________________________ C3H8 + 5 O2 -> 3 CO2 + 4 H2O
I tried doing these they are due by 12:00 please help i have 2 more like this

Answer 1

The balanced chemical reaction is expressed as:

C3H8 + 5 O2 -> 3 CO2 + 4 H2O

We are given the amount of water produced. We use this amount for the calculations. We do as follows:

16.3 mol H2O ( 1 mol C3H8 / 4 mol H2O ) = 4.075 mol C3H8 needed

Hope this answers the question. Have a nice day.

Answer 2

Answer:

20.375 moles of oxygen are necessary to completely react with propane to produce 16.3 moles of water.

Explanation:

$C_3H_8 + 5O_2\rightarrow 3 CO_2 + 4H_2O$

Mole sof water formed = 16.3 moles

According to reaction , 4 moles of water are obtained from 5 moles of oxygen.

Then 16.3 moles of oxygen will be obtained from:

$\frac{5}{4}\times 16.3 mol =20.375 mol$ of oxygen

20.375 moles of oxygen are necessary to completely react with propane.