Answer: The molarity of this solution is 2.5 M.
Explanation:
Given : [tex]V_1 = 44 mL[/tex], [tex]V_2 = 176 mL[/tex]
[tex]M_1 = 10 M[/tex]
Therefore, the value of molarity of the solution is calculated using following formula.
[tex]M_1 \times V_1 = M_2 \times V_2[/tex]
Substitute the values into above formula as follows.
[tex]M_1 \times V_1 = M_2 \times V_2\\10 M \times 44 mL = M_2 \times 176 mL\\M_2 = \frac{10 M \times 44 mL}{176 mL}\\= 2.5 M[/tex]
Hence, molarity of the solution is 2.5 M.