Answer:
The correct option is (c).
Explanation:
Given that,
The energy of a photon is, [tex]E=3.38\times 10^{-19}\ J[/tex]
We need to tell the color of this light. We know that, the energy of a photon is given by :
[tex]E=\dfrac{hc}{\lambda}[/tex]
Where
c is the speed of light
[tex]\lambda=\dfrac{hc}{E}\\\\\lambda=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{3.38 \times 10^{-19}}\\\\\lambda=5.88\times 10^{-7}\ m\\\\\lambda=588\ nm[/tex]
The wavelength of yellow light is approx 580 nm. Hence, we can say that this photon corresponds to yellow light.
