Question

can anyone help with this please !!!!

Answer 1

Answer:

"Add equations A and B to eliminate $y$. Add equations A and C to eliminate $y$".

Step-by-step explanation:

Let be the following system of linear equations:

$4\cdot x + 4\cdot y + z = 24$ (1)

$2\cdot x - 4\cdot y +z = 0$ (2)

$5\cdot x - 4\cdot y - 5\cdot z = 12$ (3)

1) We eliminate $y$ by adding (1) and (2):

$(4\cdot x + 2\cdot x) +(4\cdot y - 4\cdot y) + (z + z) = 24 + 0$

$6\cdot x +2\cdot z = 24$ (4)

2) We eliminate $y$ by adding (1) and (3):

$(4\cdot x + 5\cdot x) +(4\cdot y - 4\cdot y) +(z -5\cdot z) = (24 + 12)$

$9\cdot x -4\cdot z = 36$ (5)

Hence, the correct answer is "Add equations A and B to eliminate $y$. Add equations A and C to eliminate $y$".