Two decimals numbers, to the thousandths, that have a sum of about 5 and a difference of about 3. Then do the math to prove it works.

Respuesta :

Answer:

The numbers are approximately: 4.000 and 1.000

Step-by-step explanation:

The given parameters can be expressed as:

[tex]\frac{x}{1000} + \frac{y}{1000} \approx 5[/tex]

[tex]\frac{x}{1000} - \frac{y}{1000} \approx 3[/tex]

Required

Determine the numbers

In each of the equations, multiply by 1000

[tex]1000 * [\frac{x}{1000} + \frac{y}{1000} \approx 5][/tex]

[tex]x + y \approx 5000[/tex]

[tex]1000 * [\frac{x}{1000} - \frac{y}{1000} \approx 3][/tex]

[tex]x-y \approx 3000[/tex]

So, we have:

[tex]x + y \approx 5000[/tex]

[tex]x-y \approx 3000[/tex]

Add the two equations

[tex]x + x + y - y \approx 5000 + 3000[/tex]

[tex]2x \approx 8000[/tex]

Solve for x

[tex]x \approx 8000/2[/tex]

[tex]x \approx 4000[/tex]

Substitute [tex]x \approx 4000[/tex] in [tex]x + y \approx 5000[/tex]

[tex]4000 + y \approx 5000[/tex]

[tex]y \approx 5000 - 4000[/tex]

[tex]y \approx 1000[/tex]

Using:

[tex]\frac{x}{1000} + \frac{y}{1000} \approx 5[/tex]

We have:

[tex]\frac{4000}{1000} + \frac{1000}{1000} \approx 5[/tex]

[tex]4.000 + 1.000 \approx5[/tex]

This implies that, the numbers approximates to 4.000 and 1.000, respectively.

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