Question

Mass box a = 10 grams; mass box b = 5 grams; mass box c—made of one a and one b how many grams of a would be needed to give the same number of particles: as 7.5 grams of b? as 2.5 grams? as 12.5 grams? as 1 gram?

Answer 1

As 1 gram................

Answer 2

Answer:

The correct answers are 15g A, 5g A, 25g A and 2g A.

Explanation:

First we must take into account the masses of A ($m_{A}$) and B (

$m_{B}$) :

$m_{A}$ = 10g

$m_{B}$ = 5g

 Now, in the case of 7.5 g of B:

$m_{A1}$ = (7.5g B / 5g B) * 10g A = 15gA

For the case of 2.5 g of B:

$m_{A2}$ = (2.5g B / 5g B) * 10g A = 5gA

For the case of 12.5 g of B:

$m_{A3}$ = (12.5g B / 5g B) * 10g A = 25gA

For the case of 1 g of B:

$m_{A4}$ = (1g B / 5g B) * 10g A = 2gA

Have a nice day!