Answer:
Kite is a quadrilateral in which two disjoint pairs of consecutive sides are congruent
Given: In kite PQRS
where PR and SQ are the diagonals of Kite respectively as shown in the figure given below.
Given: TQ = 3 cm and TP = 4 cm
Let PR is the main diagonal and SQ is the cross diagonal of kite PQRS as shown in figure, also let T is the intersection point of PQRS.
By Property of Kite, diagonal SQ bisects PR at perpendicular angle i.e, 90 degree.
i,e
Then, in right angle ΔQTP
[tex]PQ = \sqrt{TQ^2+TP^2}[/tex] [Using Pythagoras theorem]
Substitute the given values of TQ and TP we have;
[tex]PQ = \sqrt{3^2+4^2} =\sqrt{9+16} =\sqrt{25} = 5 cm[/tex]
Also, PQ = SP [by definition of kite]
therefore, the side SP = 5 cm.
