SA = 2tr2 + 2trh (Use 3.14 for .) How much metal is needed to create a cylindrical can with a height of 5 inches and a base diameter of 3 inches? square inches Do NOT round your answer.​

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Answer:

[tex]SA=61.26\ \text{inches}^2[/tex]

Step-by-step explanation:

The surface area of a cylinder is given by :

[tex]SA=2\pi r^2+2\pi rh[/tex]

Where

r is radius and h is height of the cylinder

We have, h = 5 inches and r = 3/2 = 1.5 inches

Put all the respected values.

[tex]SA=2\pi \times (1.5)^2+2\pi \times 1.5\times 5\\\\SA=61.26\ \text{inches}^2[/tex]

So, the surface area of the cylinder is equal to [tex]61.26\ \text{inches}^2[/tex].

Answer:

Answer: 61.23 / {I'm right trust me Acellus 2022}

Step-by-step explanation:

how much metal is needed to create a cylindrical can with a height of 5 inches and a base diameter of 3 inches

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