Answer:
[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9[/tex]
Step-by-step explanation:
Given
[tex]tan\theta = 3[/tex]
Required
Find
[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)[/tex]
Calculate [tex]tan(\theta + \pi) \ and\ tan(\theta+2\pi)[/tex]
Using tan rule
[tex]tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}[/tex]
So:
[tex]tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}[/tex]
[tex]tan(\theta + \pi) = \frac{tan\theta}{1 }[/tex]
[tex]tan(\theta + \pi) = \tan\theta[/tex]
[tex]tan(\theta+2\pi)[/tex]
[tex]tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}[/tex]
[tex]tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}[/tex]
[tex]tan(\theta + 2\pi) = \tan\theta[/tex]'
'So:
[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)[/tex] [tex]= tan\theta +tan\theta +tan\theta[/tex]
[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3[/tex]
[tex]tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9[/tex]
