Answer:
[tex]\frac{3x-6}{x(x-3)}[/tex]
Step-by-step explanation:
We require the denominators of the fractions to be common.
Multiply numerator/denominator of first fraction by x - 3
Multiply numerator/denominator of second fraction by x
Then
= [tex]\frac{2(x-3)}{x(x-3)}[/tex] + [tex]\frac{x}{x(x-3)}[/tex] ( simplify numerators, leaving the common denominator
= [tex]\frac{2x-6+x}{x(x-3)}[/tex]
= [tex]\frac{3x-6}{x(x-3)\\}[/tex]