In which scenario is the greatest amount of work done on a wagon?

A force of 55 N moves it 8 m.
A force of 60 N moves it 6 m.
A force of 50 N moves it 5 m.
A force of 40 N moves it 10 m.

Respuesta :

Answer:

The first scenario!

Explanation:

W=F*d

a) 55*8= 440J

b) 60*6= 360J

c) 50*5= 250J

d) 40*10= 400J

The scenario with the greatest amount of work done on a wagon is "A force of 55 N moves it 8 m" and the Work done is 440N.m.

What is Work done?

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

W = F × d

Where F is force applied and d is distance travelled.

From the question;

A force of 55 N moves it 8 m

W = 55N×8m = 440N.m

A force of 60 N moves it 6 m.

W = 60N×6m = 360N.m

A force of 50 N moves it 5 m.

W = 50N×5m = 250N

A force of 40 N moves it 10 m.

W = 40N×10m = 400N.m

Therefore, the scenario with the greatest amount of work done on a wagon is "A force of 55 N moves it 8 m" and the Work done is 440N.m.

Learn more about work done: brainly.com/question/26115962

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