Answer: a. 6.8 moles of water
b. 41.6 moles of carbon dioxide
Explanation:
The balanced chemical equation for formation of water is:
[tex]2H_2+O_2\rightarrow 2H_2O[/tex]
According to stoichiometry :
1 mole of [tex]O_2[/tex] produces = 2 moles of [tex]H_2O[/tex]
Thus 3.4 moles of [tex]O_2[/tex] produce =[tex]\frac{2}{1}\times 3.4=6.8moles[/tex] of [tex]H_2O[/tex]
The balanced chemical equation for combustion of butane is:
[tex]2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O[/tex]
According to stoichiometry :
1 mole of butane produces = 8 moles of [tex]CO_2[/tex]
Thus 5.2 moles of butane produce =[tex]\frac{8}{1}\times 5.2=41.6moles[/tex] of [tex]CO_2[/tex]