Answer:
6.36 m³
Explanation:
Using the general gas law
P₁V₁/T₁ = P₂V₂/T₂
Given that P₁ = 1.0 atm, V₁ = 0.8 m³ and T₁ = 20 °C = 273 + 20 = 293 K and P₂ = 0.10 atm, V₂ = unknown and T₂ = -40 °C = 273 + (-40) = 273 - 40 = 233 K
So, V₂ = P₁V₁T₂/P₂T₁
Substituting the values of the variables into the equation, we have
V₂ = 1.0 atm × 0.8 m³ × 233 K/0.10 atm × 293 K
V₂ = 186.4 atm-K-m³/29.3 atm-K
V₂ = 6.36 m³
So, the new volume of the balloon is 6.36 m³.