Help with circles please.!
Asapppp

Answer:
b. 54°
Step-by-step explanation:
By the property of intersecting tangent and secant outside of a circle, we have:
[tex] m\angle Q =\frac{1}{2} (200\degree - 92\degree) [/tex]
[tex] m\angle Q =\frac{1}{2} \times 108\degree [/tex]
[tex] m\angle Q =54\degree [/tex]