Question

Binomial Theorem

The constant term in the expansions of
$(px^{3} + \frac{q}{x ^{3} } )^{8}$
and
$(p {x}^{2} + \frac{q}{ {x}^{2} } ) ^{4}$
are equal, and p and q are both greater than zero. Express p in terms of q.

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Answer 1

Answer:

$\frac{p^{4} x^{24}+6p^{2}q^{2}x^{12}+q^{4}+4p^{3}qx^{18}+4pq^{3}x^{6}}{x^{12} }$

Step-by-step explanation: